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kpoxa
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kpoxa
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Sumithra
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kpoxa
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Sumithra

1) July '02 median=1.02x
Jan '02 m=x

S1: x=1.04y insuff, since we do not know y
S2: 0.04y=1020 again insuff 'cause we do not know the relationship bet. y and x
Together: can find y and therefore x


this is exactly what Kaplan says, but I do not agree with that. choice 2 gives "Country X increased by $1,020" which is amount of increase. I could not calculate the median household amount using information provided. Can you shed more light n this?
thanks
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Sumithra
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Here y=median in July'01
Since 0.04y=1020
y=1020/0.04=25500
Therefore, x=25500+1020=26520
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AdrianG
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C is the answer for both questions :)
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Andr359
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kpoxa
From January 1, 2002 to July 1, 2002, the median household income in Country X increased by 2%. What was the median household income in Country X on January 1, 2002?

(1) From July 1, 2001 to January 1, 2002, the median household income in Country X increased by 4%.

(2) From July 1, 2001 to January 1, 2002, the median household income in Country X increased by $1,020.


(1) Right away: not sufficient.
(2) Same as in (1).
(1&2) 1020 = 4%X, X = median household income in July 1, 2001. Thus, we are able to find X and Y = median household income in January 1, 2002. Therefore, we can solve the problem => C.

We don´t make use of the "2% increase" data in this DS question.
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Andr359
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kpoxa
Maria had twice as many suits in the year 1995 as she did in the year 1990. How many suits did Maria have in the year 1990 ?

(1) Maria had twice as many suits in the year 2000 as she did in the year 1995

(2) Maria had 2 more suits in the year 2000 than she did in the year 1995.


Let X = # of suits in 1995. Y = # of suits in 2000.
(1) Y = 2X. Insuff => B, C or E.
(2) Y = X + 2. Insuff => C or E.
(1&2) 2X = X + 2 => X = 2, Y = 4. Suff => C.



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