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G(x) is the greatest integer less than or equal to x and L(x) is the s

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G(x) is the greatest integer less than or equal to x and L(x) is the smallest integer greater than or equal to x. Which of the following can be the value of L(1.1)-G(1.1)?

A. -2 B. -1 C. 0 D. 1 E. 2

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New post 07 Dec 2016, 01:32
==> You get L(1.1)-G(1.1)=2-1=1, and therefore the answer is D.

Answer: D
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Re: G(x) is the greatest integer less than or equal to x and L(x) is the s  [#permalink]

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New post 06 Nov 2019, 20:28
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MathRevolution wrote:
G(x) is the greatest integer less than or equal to x and L(x) is the smallest integer greater than or equal to x. Which of the following can be the value of L(1.1)-G(1.1)?

A. -2 B. -1 C. 0 D. 1 E. 2


Since L(1.1) = 2 and G(1.1) = 1, L(1.1) - G(1.1) = 2 - 1 = 1.

Answer: D
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Re: G(x) is the greatest integer less than or equal to x and L(x) is the s  [#permalink]

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New post 19 Nov 2019, 07:30
Can someone explain how L(1.1) is 2 and G(1.1) is one?
I am missing something here..

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Re: G(x) is the greatest integer less than or equal to x and L(x) is the s  [#permalink]

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New post 19 Nov 2019, 08:12
can anyone plz explain why is it 2 and 1 ?
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G(x) is the greatest integer less than or equal to x and L(x) is the s  [#permalink]

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New post 23 Nov 2019, 05:34
Pooja132 wrote:
can anyone plz explain why is it 2 and 1 ?


Hello Pooja,

There are several similar problems to this one out there, the basic assumption is that you either round up or down to next highest or lowest integer.

"G(x) is the greatest integer less than or equal to x and L(x) is the smallest integer greater than or equal to x."

G(X)

If x is 1 G (x) would be 1, as it is an integer already.
x is 1.1 though, therefore we need to round down to the greatest integer LESS than x (1.0)

L(X)

If x is 1 then L (x) would be 1, it is an integer already
x is 1.1 though, therfore we need to round up to the next smallest integer GREATER than x (2.0)

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Re: G(x) is the greatest integer less than or equal to x and L(x) is the s  [#permalink]

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New post 23 Nov 2019, 07:23
Psyllium9 wrote:
Can someone explain how L(1.1) is 2 and G(1.1) is one?
I am missing something here..

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Hi
The question pertains to integer function. They are of two types i.e smallest integer function and greatest integer function.

Smaller Integer function is the value of the smallest integer greater than or equal to the x in F(x).
Let us say that F(x) and x is 3.879 nor smallest integer function is F(3.879) = 4

Likewise we have greatest integer function F(x)
Were the function represents the the greatest integer smaller that the x value in F(x)

Take the same example as above F(x) and x=3.879 now F(3.879) would be 3
So you see we can have two different values.
Hope it is clear.
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Re: G(x) is the greatest integer less than or equal to x and L(x) is the s  [#permalink]

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New post 23 Nov 2019, 08:22
MathRevolution wrote:
G(x) is the greatest integer less than or equal to x and L(x) is the smallest integer greater than or equal to x. Which of the following can be the value of L(1.1)-G(1.1)?

A. -2 B. -1 C. 0 D. 1 E. 2


L(1.1) = 2
G(1.1) = 1
L(1.1) - G(1.1) = 2-1 = 1

IMO D

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Re: G(x) is the greatest integer less than or equal to x and L(x) is the s   [#permalink] 23 Nov 2019, 08:22
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