Splendidgirl666 wrote:

If the volume of the cone is SH/3 where S is the area of the base and H the height. AB=BC. What is the ratio of the volume of the cone (with BC as height) to the volume of the rest of the cone (with AB as height). (for graph see attached. Didn't know how to add picture to this post)

1. 1:3

2. 1:4

3. 1:6

4. 1:7

5. 1:8

Thanks for helping. I must have forgotten something about cone characteristics here...

Let r be the radius of the cone. S = pi * r^2

So, radius of smaller cone = r/2

Volume of smaller cone = 1/3* pi * (r/2)^2 *H/2 = 1/3*pi*r^2*H/8

(AB= BC = H/2)

Volume of the rest of the cone = 1/3* pi * r^2 - 1/3*pi*r^2*H/8 = 1/3*7/8*pi*r^2*H

Volume of smaller cone/Volume of the rest of the cone = 1/7

Answer D
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