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17 Jan 2015, 13:57
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A cube has length x, a surface area y, and a volume z. Which of the following must be true?
A. xy/z - y/x = 0
B. x^2y/z - y/x = 0
C. xz/x^2y - x^2/xy = 0
D. x(√y)/√z - x^2/y = 0
E. (√z)/xy - (√y)/x^2 = 0
Is there a simpler way to solve this rather than taking individual value combinations and checking each option.
Regards,
A. xy/z - y/x = 0
B. x^2y/z - y/x = 0
C. xz/x^2y - x^2/xy = 0
D. x(√y)/√z - x^2/y = 0
E. (√z)/xy - (√y)/x^2 = 0
Is there a simpler way to solve this rather than taking individual value combinations and checking each option.
Regards,
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17 Jan 2015, 21:57
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We can solve it using units
If x is in m(meters) then y will be m^2 then z will be m^3
A cannot be true as m*m^2/m^3 - m^2/m.. first entity does not have a unit so you cannot subtract it from the second unit which has meter unit
B Can be true as it is meter - meter
C cannot be true : No unit - Meter unit
D cannot be true: √meter unit - no unit
E cannot be true: 1/meter*√meter unit - 1/meter unit
So, answer will be B
Hope it helps!
If x is in m(meters) then y will be m^2 then z will be m^3
A cannot be true as m*m^2/m^3 - m^2/m.. first entity does not have a unit so you cannot subtract it from the second unit which has meter unit
B Can be true as it is meter - meter
C cannot be true : No unit - Meter unit
D cannot be true: √meter unit - no unit
E cannot be true: 1/meter*√meter unit - 1/meter unit
So, answer will be B
Hope it helps!
amidamani13
A cube has length x, a surface area y, and a volume z. Which of the following must be true?
A. xy/z - y/x = 0
B. x^2y/z - y/x = 0
C. xz/x^2y - x^2/xy = 0
D. x(√y)/√z - x^2/y = 0
E. (√z)/xy - (√y)/x^2 = 0
Is there a simpler way to solve this rather than taking individual value combinations and checking each option.
Regards,
A. xy/z - y/x = 0
B. x^2y/z - y/x = 0
C. xz/x^2y - x^2/xy = 0
D. x(√y)/√z - x^2/y = 0
E. (√z)/xy - (√y)/x^2 = 0
Is there a simpler way to solve this rather than taking individual value combinations and checking each option.
Regards,
19 Jan 2015, 01:10
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Thanks a ton...really helpful....
Regards,
Regards,
