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LM
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eschn3am, Agree with your calculations.
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eschn3am
Equilateral Triangle means = angles and sides. Arc AB = BC = CA. If ABC = 24, then each segment is = 12 and the circumference of the circle is 36.

2(pi)r = 36
pi(r) = 18
r = 18/pi

but we want to know the diameter, since the diameter = 2r then d = 36/pi

Is that one of the answer choices?

how do we know that the circumference is 36 ? Is this a property/rule ?
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eschn3am
Equilateral Triangle means = angles and sides. Arc AB = BC = CA. If ABC = 24, then each segment is = 12 and the circumference of the circle is 36.

2(pi)r = 36
pi(r) = 18
r = 18/pi

but we want to know the diameter, since the diameter = 2r then d = 36/pi

Is that one of the answer choices?

how do we know that the circumference is 36 ? Is this a property/rule ?

because 2/3 of the circumference is 24 (Arc ABC). If 2/3 = 24, then 3/3 = 36.
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i think im just not seeing how arc length corresponds to circumference. Whats the relationship there ?
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pmenon
i think im just not seeing how arc length corresponds to circumference. Whats the relationship there ?

circumference= AB+BC+CA
due to symmetry (equilateral triangle): AB=BC=CA
Therefore,
circumference= AB+BC+CA = ABC+CA = ABC+1/2ABC = 3/2 ABC =24*3/2 =36
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pmenon
i think im just not seeing how arc length corresponds to circumference. Whats the relationship there ?

circumference= AB+BC+CA
due to symmetry (equilateral triangle): AB=BC=CA
Therefore,
circumference= AB+BC+CA = ABC+CA = ABC+1/2ABC = 3/2 ABC =24*3/2 =36

understood, but im trying to understand the root of this relationship, i.e. does this apply for any triangle in a circle ? And, how is it that adding up the sides of a triangle give you the circumference ?
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He's adding up the 3 arcs, not the sides of the triangle. and it works for this situations because it's an equilateral triangle, meaning the sides and angles are all identical to one another...meaning it breaks the circumference up into 3 equal sections.
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pmenon
walker
pmenon
i think im just not seeing how arc length corresponds to circumference. Whats the relationship there ?

circumference= AB+BC+CA
due to symmetry (equilateral triangle): AB=BC=CA
Therefore,
circumference= AB+BC+CA = ABC+CA = ABC+1/2ABC = 3/2 ABC =24*3/2 =36

understood, but im trying to understand the root of this relationship, i.e. does this apply for any triangle in a circle ? And, how is it that adding up the sides of a triangle give you the circumference ?

each side-segment is equal so based on symmetry the circle circumference can be divided into 3 arcs of equal length. We have measure of 2 arcs (i.e. 24). So add another 12 and equate 36 to 2Pir.

I believe if you have the ratio of triangle sides, you can work out how the entire circumference is divided among the vertices.
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srp
I believe if you have the ratio of triangle sides, you can work out how the entire circumference is divided among the vertices.

You can but it will be hard. The segments have ratio: a:b:c, where a,b,c are measure of angles.
From the triangle you will find cos(a), cos(b), cos(c) (or sin, tg). And it will be difficult to operate with function such as arccos().

let d - the diameter of the circle,
n - one of the side of the inscribed triangle.

segment=d*arccos(n/d)
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srp
I believe if you have the ratio of triangle sides, you can work out how the entire circumference is divided among the vertices.

You can but it will be hard. The segments have ratio: a:b:c, where a,b,c are measure of angles.
From the triangle you will find cos(a), cos(b), cos(c) (or sin, tg). And it will be difficult to operate with function such as arccos().

let d - the diameter of the circle,
n - one of the side of the inscribed triangle.

segment=d*arccos(n/d)

Right! but I dont' think on GMAT they will give you ratios to be worked through sincostan. The triangles will be known ones or ratios may already be provided
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srp

Right! but I dont' think on GMAT they will give you ratios to be worked through sincostan. The triangles will be known ones or ratios may already be provided

I agree. GMAT is more tricky than hard in quant. :)
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LM
This too, I thought I could solve directly by knowing the parameter as 3 times the given value of arc, and getting the diameter, but got it wrong.


Since its an equilateral triangle We know the third side must be 1/3 of the total of the circumfrence of the circle. (jeez too many of's :P)

anyway that means C=36 Thus the diameter is just 36/pi ~12



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