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study
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GEOMETRY-gmatprep qs 16 Jan 2009, 09:30
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attached. sorry don't know how to copy the image as jpeg.
would appreciate if someone who knows can put it as an image in his reply. Thanks.



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tusharvk
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GEOMETRY-gmatprep qs 16 Jan 2009, 10:44
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study
attached. sorry don't know how to copy the image as jpeg.
would appreciate if someone who knows can put it as an image in his reply. Thanks.
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I don't know either. Is the answer one you chose or OA?
Anyway, here is a little bit cumbersome way to solve it:
Let C be the center of the circle. cr=co = 9.
<crp=<rpq=35.
Further because of isosceles triangle,
cpr=rpq=35
Thus, <cpq=70
Angle submitted by arc on center=<pcq=40.
Length of the minor arc = pi*18*40/360=2*pi
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study
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GEOMETRY-gmatprep qs 16 Jan 2009, 11:30
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Thanks!

OA is A, which is 2pi.
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GMAT TIGER
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GEOMETRY-gmatprep qs 16 Jan 2009, 12:00
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tusharvk
study
attached. sorry don't know how to copy the image as jpeg.
would appreciate if someone who knows can put it as an image in his reply. Thanks.

I don't know either. Is the answer one you chose or OA?
Anyway, here is a little bit cumbersome way to solve it:
Let C be the center of the circle. cr=co = 9.
<crp=<rpq=35.
Further because of isosceles triangle,
cpr=rpq=35
Thus, <cpq=70
Angle submitted by arc on center=<pcq=40.
Length of the minor arc = pi*18*40/360=2*pi
Show more

Fully agree with PQ = 2 Pi R (40/360) = 2 (pi)

A.
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GEOMETRY-gmatprep qs 16 Jan 2009, 13:51
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yup

2pi

PQ = (40/360) 2 pi R
PQ = ( 40/360 ) 2 pi . 9
PQ = 2pi

https://www.graduatetutor.com



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!