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# Give the arithmetic mean of A and B.

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Math Expert
Joined: 02 Sep 2009
Posts: 58335
Give the arithmetic mean of A and B.  [#permalink]

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31 Jan 2019, 01:37
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Difficulty:

25% (medium)

Question Stats:

81% (01:00) correct 19% (00:58) wrong based on 42 sessions

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What is the arithmetic mean of A and B.

(1) A rectangle with length A and width B has area 500.

(2) A triangle with base of length A and height B has area 250

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Re: Give the arithmetic mean of A and B.  [#permalink]

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31 Jan 2019, 03:22
Bunuel wrote:
What is the arithmetic mean of A and B.

(1) A rectangle with length A and width B has area 500.

(2) A triangle with base of length A and height B has area 250

#1
x*y = 500
5^3 * 2^2
there can be total 12 factors of 500 and we can have many different mean values ; in sufficient

#2
x*y= 0.5*250
x*y= 500
again same reason as #1
in sufficient
combining both wont given us single value of x & y
IMO E
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Re: Give the arithmetic mean of A and B.  [#permalink]

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31 Jan 2019, 07:31
1

Solution

To find:
• The arithmetic mean of A and B = $$\frac{(A + B)}{2}$$

Analysing Statement 1
“A rectangle with length A and width B has area 500”
• Implies, A * B = 500
• From this we cannot find the value of A + B

Therefore, statement 1 is not sufficient

Analysing Statement 2
“A triangle with base of length A and height B has area 250”
• Implies, $$\frac{1}{2} * A * B = 250$$
• From this we cannot find the value of A + B

Therefore, statement 2 is not sufficient

Combining Both Statements
Combining both statements, we have A * B = 500
• From this we cannot find the value of A + B

Therefore, both statements together are not sufficient

Hence, the correct answer is Option E

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Re: Give the arithmetic mean of A and B.   [#permalink] 31 Jan 2019, 07:31
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