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12 Sep 2018, 00:13
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
60% (01:58) correct
40%
(02:02)
wrong
based on 39
sessions
History
Date
Time
Result
Not Attempted Yet
Given a rectangle and circle that share a center with a vertex of a triangle as shown above, what is the area of the shaded region?
(1) Each side of the inscribed rectangle is 2.
(2) The ratio of the area of the rectangle to the area of the circle is d^2 to 2πr^2, where d is the diameter of the circle and r is the radius.
Attachment:
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12 Sep 2018, 09:21
Kudos
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Bunuel
(1) Each side of the inscribed rectangle is 2.
that means the rectangle is a square
now,
the radius of the circle =\(\frac{diagonal of the square}{2}\)= \(\sqrt{2}\)
we now have all the three sides of the triangle ,\(\sqrt{2}\),\(\sqrt{2}\),2
area of the sector =\(\pi r^2\) @/360
r=\(\sqrt{2}\)
the diagonals of a square intersect at 90 degrees .
therefore @ = 90
sufficient
(2) The ratio of the area of the rectangle to the area of the circle is d^2 to 2πr^2, where d is the diameter of the circle and r is the radius.
we get the value as 7/11
insufficient
A
12 Sep 2018, 11:05
Kudos
Bookmarks
Bunuel
Statement 1 - If each side of a rectangle is equal, then it's a square. Given the sides of square=2, so radius of circle will be 2root(2).
Area of shaded region = (Area of circle - Area of square) /4. Hence sufficient.
Statement 2 - Simplifying the equation revealed that the rectangle is a square but no dimensions are given. Hence not sufficient.
Hence A.
Cheers!
