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bmwhype2
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Himalayan
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bmwhype2
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Himalayan
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bmwhype2
the exact question

(3, 5, 9, 13, y)

if the average (arithemetic mean) of the set of numbers above is equal to the median of the same set of number above, then what is the value of y?

a 7
b 8
c 10
d 15
e 17


from my calculation above, y = 15
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gmatiscoming
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the are giving you the median as 9 and telling you the mean will also equal n9. i guess this one is tricky, since sets don't have to be in order - although you have to put them in order to find the median, they aren't flat out telling you that the set is in ascending order.

but the calculation is

(3+5+9+13+y)/5 =9
30+y = 45
y =15
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saurster
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gmatiscoming; it appears that the set is ordered (ascending) so they don't need to tell you. However, its always better to check anyways...good job
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Bluebird
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I agree with the answer of 15.

Assuming that the set is not ordered, we know that the mean = (30+y)/5

In order for the mean to be 3, (30+y) would have to equal 15, therefore, y would equal -15. Not a choice.

In order for the mean to equal 5, (30+y) would have to equal 25, therefore y = -5. Again, not a choice.

In order for the mean to equal 9, (30+y) would have to equal 45, therefore, y=15. This is a choice. A quick glance shows that y=15 also satisfies 9 as the median.

Answer: y=15



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