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cavanbas
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Given that 3-x1/2=(2x-7)1/2, what is x? (i.e., 23 Jul 2004, 02:56
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1. Given that 3-x1/2=(2x-7)1/2, what is x?
(i.e., "1/2" means square root.)

2. Given that x+y=11 and x1/2=y-5, solve for x and y.







1. Ans. x=4 or 64.
2. Ans. x=4, y=7; x=9, y=2.
Any suggestions on the best way to solve these two problems?



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hardworker_indian
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Given that 3-x1/2=(2x-7)1/2, what is x? (i.e., 23 Jul 2004, 09:10
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If this Q had been a GMAT PS, substituting answer choices might have made it easy...
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Emmanuel
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Given that 3-x1/2=(2x-7)1/2, what is x? (i.e., 23 Jul 2004, 09:27
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cavanbas
1. Given that 3-x1/2=(2x-7)1/2, what is x?
(i.e., "1/2" means square root.)

2. Given that x+y=11 and x1/2=y-5, solve for x and y.







1. Ans. x=4 or 64.
2. Ans. x=4, y=7; x=9, y=2.
Any suggestions on the best way to solve these two problems?
Show more


Just take squares of the left and right-hand expressions and make a replacement: let z = SQRT(x). Then you'll get quadratic equation, which you know how to solve. Then you'll get 2 roots, just don't consider negative root.

Best regards,

Emmanuel.
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Yan
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Given that 3-x1/2=(2x-7)1/2, what is x? (i.e., 27 Jul 2004, 08:43
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1. I don't think x can be 64.
2. I don't think y can be 2.

Am I wrong or the answers are wrong? :?:
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venksune
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Given that 3-x1/2=(2x-7)1/2, what is x? (i.e., 27 Jul 2004, 23:06
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Applying normal brute force method, the answers for x and y is right. Yan, I think you are missing something - may be some simple calculation errors. Check it out.

Took about 2 mins fully. I am sure if there is any other easier method other than backsolving.
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Yan
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Given that 3-x1/2=(2x-7)1/2, what is x? (i.e., 28 Jul 2004, 01:02
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venksune
Applying normal brute force method, the answers for x and y is right. Yan, I think you are missing something - may be some simple calculation errors. Check it out.

Took about 2 mins fully. I am sure if there is any other easier method other than backsolving.
Show more


I did come up with X=64 for the first equation and x=9, y=2 for the second equation, BUT when I took them back to the equation, I got these.

1. (the first equation) 3-x1/2=3-64*sqrt2=-5 and (2x-7)1/2=(2*64-7)*sqrt2=11

2. (the second equation) x1/2=9*sqrt2=3 and y-5=2-5=-3

Is there anything wrong with my caculation? :?:



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!