Bunuel
Given that b is more than 90 percent of a, is b < 65?
(1) a > 75
(2) a - b > 5
Target question: Is b < 65? Given: b is more than 90 percent of a We can write: b > (9/10)a
Multiply both sides by 10/9 to get: (10/9)b > a
Rearrange:
a < (10/9)b Statement 1: a > 75 Rearrange: 75 < a
Combine with given information to get: 75 < a <
(10/9)b From this, we can conclude: 75 < (10/9)b
Multiply both sides by 9/10 to get: (9/10)75 < b
Simplify: 67.5 < b
If b is greater than 67.5, then we can be certain that b is NOT less than 65.
So, the answer to the target question is
NO, b is NOT less than 65Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: a - b > 5Add b to both sides: a > b + 5
Rearrange: b + 5 < a
Combine with given information to get: b + 5 < a <
(10/9)b From this, we can conclude: b + 5 <
(10/9)bMultiply both sides by 9 to get: 9b + 45 < 10b
Subtract 9b from both sides:
45 < bSo, b could equal 46, in which case
b < 65Conversely, b could equal 100, in which case
b > 65Since we can’t answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Answer: A
Cheers,
Brent