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02 Apr 2015, 15:39
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
50% (01:00) correct
50%
(01:24)
wrong
based on 2
sessions
History
Date
Time
Result
Not Attempted Yet
Given the following: x1 = 2, x2 = -1, x3 = -2, x4 = 5, x5 = -4, x6 = 8, find
A. 7
B. 9
C. 11
D. 20
E. 26
Attachment:
Eq.png
A. 7
B. 9
C. 11
D. 20
E. 26
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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02 Apr 2015, 16:22
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goodyear2013
Dear goodyear2013,
I'm happy to respond.
With all due respect, I believe something is amiss with how you posted the problem. The equation you posted in the picture has a clear value, although not the one you report as the OA. What is entirely cryptic to me is the first line, "Given the following: x1 = 2, etc." That doesn't appear to have any connection to the equation at all or to anything actually asked. There are no x's in the equation that is to be evaluated. Something is very fishy here. Were two different problems conflated? The expression you have in the picture is a summation symbol. This symbol appears frequently in advanced mathematics, but I have never seen it in a GMAT problem. It's actually not that hard, but I have never see the GMAT refer to it.
\(\sum_{i=1}^{3} (i^2 + 2i)\)
means that we are going to plug the values i = 1, i = 2, and i = 3 into that algebraic expression, \((i^2 + 2i)\), which will give us three values, and then we are going to add those three values up.
When i = 1, \((i^2 + 2i)= 1 + 2 = 3\)
When i = 2, \((i^2 + 2i)= 4 + 4 = 8\)
When i = 3, \((i^2 + 2i)= 9 + 6 = 15\)
3 + 8 + 15 = 26
This is choice (E), but does not match the OA you listed. Once again, this is not math you would need to know for the GMAT.
Please let me know where you found this problem and any corrections to it.
Mike
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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