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24 Apr 2018, 06:12
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Given the graphs of \(y = \frac{(x^2 - 3x - 10)}{(x + 2)}\) and \(y= 3x - 1\) in the xy-plane. Which of the following can be the number of points of intersection of the two graphs?
I. 0
II. 1
III. 2
(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
I. 0
II. 1
III. 2
(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
24 Apr 2018, 10:06
Kudos
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Bunuel
Given the graphs of \(y = \frac{(x^2 - 3x - 10)}{(x + 2)}\) and \(y= 3x - 1\) in the xy-plane. Which of the following can be the number of points of intersection of the two graphs?
I. 0
II. 1
III. 2
(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
I. 0
II. 1
III. 2
(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
1st equation \(y = \frac{(x^2 - 3x - 10)}{(x + 2)}\) can be written as \(y = \frac{(x+2)*(x-5)}{(x+2)}\)
or y = x-5, (provided \(x\neq{-2}\))
2nd equation y = 3x-1
solving x = -2 and y = -7, but x=-2 is not possible
So 0 values..Hence Option A
24 Apr 2018, 11:11
Kudos
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rkgstyle
Bunuel
Given the graphs of \(y = \frac{(x^2 - 3x - 10)}{(x + 2)}\) and \(y= 3x - 1\) in the xy-plane. Which of the following can be the number of points of intersection of the two graphs?
I. 0
II. 1
III. 2
(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
I. 0
II. 1
III. 2
(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
1st equation \(y = \frac{(x^2 - 3x - 10)}{(x + 2)}\) can be written as \(y = \frac{(x+2)*(x-5)}{(x+2)}\)
or y = x-5, (provided \(x\neq{-2}\))
2nd equation y = 3x-1
solving x = -2 and y = -7, but x=-2 is not possible
So 0 values..Hence Option A
Can you please explain why this is not possible?
