With the given co-ordinates find the distance between the two points using \(\sqrt{(x2-x1)^2 + (y2-y1)^2}\)

Distance between points (0,3) & (3,-3) is \(\sqrt{-3^2+-6^2}\)=\(\sqrt{45}\)

Distance between points (0,3) & (-3,-3) is \(\sqrt{3^2+-6^2}\) = \(\sqrt{45}\)

Distance between points (-3,-3) & (3,-3) is\(\sqrt{-6^2 +0}\)= 6

which is an isosceles triangle.

We need to find the height so that we can use the formula \(\frac{1}{2}\)*b*h

Height by Pythagoras theorem, h=\(\sqrt{45-6}\)= \(\sqrt{36}\)= 6

Area =\(\frac{1}{2}\)*6*6

=18

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Kudos are always welcome ... as well your suggestions