ahengartner wrote:
shameekv1989 how did you derive the equation to solve this problem?
ahengartner :- Which equation are you talking about?
\(\sqrt{(x-1)^2}\) -> When you take a square root of a variable (a perfect square) it will be an absolute value, in this cae, |x-1|
So when you open an absolute there are 2 possiblities i.e. \(x-1<0\) -> \(x<1\) and \(x-1>0\) -> \(x>1\).
And it is given in the question that x<1. So we consider only when x<1 i.e. x-1 < 0.
We write an absolute as negative when it is <0 when we open i.e. |x-1| = -(x-1) when (x-1) < 0 i.e. when x<1.
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