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rajak01
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Hi rajak01,

Actually, in the probability of events E and F, which are represented by P(E) and P(F), the overlap is present in each category and if we add P(E) and P(F) the overlap is being added twice, and that is why we subtract it once to get the P(E union F). This is similar to the Venn diagram for two sets case.

Dabral
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Hi rajak01,

Actually, in the probability of events E and F, which are represented by P(E) and P(F), the overlap is present in each category and if we add P(E) and P(F) the overlap is being added twice, and that is why we subtract it once to get the P(E union F). This is similar to the Venn diagram for two sets case.

Dabral

Oh man, this is the answer i was looking for! You are the genie! Thanks a lot mate, now i understood!
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