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racha24
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GMAT PREP 2 PS 26 Aug 2007, 13:09
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GMAT PREP 2 PS 26 Aug 2007, 13:25
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racha24
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I think 1/2
Area = 1/2 * b * h
Base will always =1
height varies, but the max height will equal to radius
Area = 1/2 * 1 * 1 = 1/2
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racha24
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GMAT PREP 2 PS 26 Aug 2007, 13:29
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bkk145
racha24
please see below.

I think 1/2
Area = 1/2 * b * h
Base will always =1
height varies, but the max height will equal to radius
Area = 1/2 * 1 * 1 = 1/2
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how can we say that the max height will equal to radius? if we are assuming that one of the radius arms is the base, then height can actually be greater than the radius right...
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bkk145
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GMAT PREP 2 PS 26 Aug 2007, 13:37
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racha24
bkk145
racha24
please see below.

I think 1/2
Area = 1/2 * b * h
Base will always =1
height varies, but the max height will equal to radius
Area = 1/2 * 1 * 1 = 1/2

how can we say that the max height will equal to radius? if we are assuming that one of the radius arms is the base, then height can actually be greater than the radius right...
Show more


If the base is 1, you have one point at the center and one point on the circle. So now, you are left with one point moving around in the circle, say point x. So, from the center of the circle to point x, the greatest possible value will be 1, in my opinion.


What the OA, btw?
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GMAT PREP 2 PS 26 Aug 2007, 14:04
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bkk145
racha24
bkk145
racha24
please see below.

I think 1/2
Area = 1/2 * b * h
Base will always =1
height varies, but the max height will equal to radius
Area = 1/2 * 1 * 1 = 1/2

how can we say that the max height will equal to radius? if we are assuming that one of the radius arms is the base, then height can actually be greater than the radius right...

If the base is 1, you have one point at the center and one point on the circle. So now, you are left with one point moving around in the circle, say point x. So, from the center of the circle to point x, the greatest possible value will be 1, in my opinion.


What the OA, btw?
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OA is 1/2, but the height should be mesured from the third vertice to base, not to the center which is one of the vertices...
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Juaz
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GMAT PREP 2 PS 26 Aug 2007, 15:07
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Max area = 2(1/2 * 1/sqrt2 * 1/sqrt2) = 1/2
height would be 1/sqrt2.
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subhen
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GMAT PREP 2 PS 26 Aug 2007, 15:47
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For a triangle to have the greatest area, it must be a right angled triangle.

In this case the two arms which are radius form the base and height of the right angled triangle. Hence the area is 1/2*1*1=1/2

Had the triangle been an equilateral triangle, the area would have been sqrt(3)/4 which is less than half.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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