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agsfaltex
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agsfaltex
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I did it the long way...
I multiplied both out and got

2x^2+4xy+2y^2
--------------------
2x^2-4xy+2y^2


When you divide out, you get

4xy
------
-4xy

I know the answer is 16. When I bring the 4xy on the bottom up to the top why doesn't it equal 16?
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Quote:
2x^2+4xy+2y^2
--------------------
2x^2-4xy+2y^2


I am not sure how you got 2x^2 and 2y^2, but regardless, once you have that, and since this is an exponent, you will subtract the denominator from the numerator:

x^2 + 2xy + 2y^2 - x^2 + 2xy - y^2

=4xy= 4

2^4
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ps_dahiya
jamesrwright3
I did it the long way...
I multiplied both out and got

2x^2+4xy+2y^2
--------------------
2x^2-4xy+2y^2


When you divide out, you get

4xy
------
-4xy

I know the answer is 16. When I bring the 4xy on the bottom up to the top why doesn't it equal 16?
How did you divide????


Am I not allowed to divide the like terms on the top and bottom?
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jamesrwright3
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rdw28
Quote:
2x^2+4xy+2y^2
--------------------
2x^2-4xy+2y^2

I am not sure how you got 2x^2 and 2y^2, but regardless, once you have that, and since this is an exponent, you will subtract the denominator from the numerator:

x^2 + 2xy + 2y^2 - x^2 + 2xy - y^2

=4xy= 4

2^4


I got it by simply squaring the x-y and the x+y on the tops and bottom and then multiplying the result by 2
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jamesrwright3
ps_dahiya
jamesrwright3
I did it the long way...
I multiplied both out and got

2x^2+4xy+2y^2
--------------------
2x^2-4xy+2y^2


When you divide out, you get

4xy
------
-4xy

I know the answer is 16. When I bring the 4xy on the bottom up to the top why doesn't it equal 16?
How did you divide????

Am I not allowed to divide the like terms on the top and bottom?

Not by splitting them.....
(2a+b)/(a+b) can be handled as
(a+a+b)/(a+b) = [a/(a+b)] +1 but you can not divide just a by a and by by b.

In summary you can split numerator but can't split denominator.



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