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GMAT-Prep PS3

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Senior Manager
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GMAT-Prep PS3 [#permalink]

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New post 21 Dec 2008, 08:14
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Even if i assume the regular price of second and third most expensive item is 20 each the total discount works out to be $14 which more than 15% of 50+20+20????
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Re: GMAT-Prep PS3 [#permalink]

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New post 21 Dec 2008, 11:09
Vivek, not sure what your question is though.

For stmt1: price of the third item will be between 0 and 20. For the two boundary values too, total discount amount will be more than 15% of sum of regular price. Hence, stmt1 is sufficient.

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Re: GMAT-Prep PS3 [#permalink]

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New post 21 Dec 2008, 11:30
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most expensive = e
other 2 = x, y


is

0.2e+0.1x+0.1y> 0.15(e+x+y)

0.05e>0.5x+0.5y

is e>x+y

from 1

is 50> 20+y , ie: is 30>y.........yes sure it is as y is already less than 20.......suff
from 2

is e>x+15......insuff

A

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Re: GMAT-Prep PS3 [#permalink]

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New post 22 Dec 2008, 08:41
yezz wrote:
most expensive = e
other 2 = x, y


is

0.2e+0.1x+0.1y> 0.15(e+x+y)

0.05e>0.5x+0.5y

is e>x+y

from 1

is 50> 20+y , ie: is 30>y.........yes sure it is as y is already less than 20.......suff
from 2

is e>x+15......insuff

A

Great Explanation, You deserve +1 for this

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Re: GMAT-Prep PS3   [#permalink] 22 Dec 2008, 08:41
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