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# GMAT-Prep PS3

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Senior Manager
Joined: 05 Jun 2008
Posts: 289

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21 Dec 2008, 09:14
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (04:21) wrong based on 1 sessions

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Even if i assume the regular price of second and third most expensive item is 20 each the total discount works out to be \$14 which more than 15% of 50+20+20????

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VP
Joined: 17 Jun 2008
Posts: 1474

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21 Dec 2008, 12:09
Vivek, not sure what your question is though.

For stmt1: price of the third item will be between 0 and 20. For the two boundary values too, total discount amount will be more than 15% of sum of regular price. Hence, stmt1 is sufficient.
Retired Moderator
Joined: 05 Jul 2006
Posts: 1731

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21 Dec 2008, 12:30
1
most expensive = e
other 2 = x, y

is

0.2e+0.1x+0.1y> 0.15(e+x+y)

0.05e>0.5x+0.5y

is e>x+y

from 1

is 50> 20+y , ie: is 30>y.........yes sure it is as y is already less than 20.......suff
from 2

is e>x+15......insuff

A
Senior Manager
Joined: 05 Jun 2008
Posts: 289

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22 Dec 2008, 09:41
yezz wrote:
most expensive = e
other 2 = x, y

is

0.2e+0.1x+0.1y> 0.15(e+x+y)

0.05e>0.5x+0.5y

is e>x+y

from 1

is 50> 20+y , ie: is 30>y.........yes sure it is as y is already less than 20.......suff
from 2

is e>x+15......insuff

A

Great Explanation, You deserve +1 for this

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: GMAT-Prep PS3 &nbs [#permalink] 22 Dec 2008, 09:41
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