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19 Sep 2010, 00:26
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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I could not figure out how to draw the figure so i have attatched the question.
thanks
thanks
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19 Sep 2010, 00:50
Kudos
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cmugeria
Since the belt is tightly wound against the circular wheel. The belt is in contact with the wheel for half its circumference (outer half on each of the two wheels). Since there are two wheels the total length of contact of the belt with the wheel is one circumference => pi. [Circumference is 2*pi*r => 2*r is 1 foot => pi]
Total length of the belt is 15 feet minus the contact of the belt with the outer circumference of the two wheels is 15-pi.
Now the belt is wrapped around hence the distance between the center of the wheels is (15-pi/2) since the belt is wound twice, once in the top, bottom of the wheel.
Answer D - (15-pi)/2.
19 Sep 2010, 03:23
Kudos
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I think the answer should be A which is 15 - pie /2
15 - (length of the circumference of the 2 semicircles at either end)
circumference of each full circle is pie; so each semi-circle is pie/2
Imagine the diameter of each circle being perpendicular to the stretched out conveyor belt in the form of a rectangle... The distance between the centers of the 2 circles will be length of the arm of the rectangle:
15 - (pie/2 + pie/2) = 15 - pie --- which will be sum of the 2 lengths of the rectangle
Since the lengths are equal --- the lenght of each arm aka the distance b/w the centers will be 15 - pie / 2
15 - (length of the circumference of the 2 semicircles at either end)
circumference of each full circle is pie; so each semi-circle is pie/2
Imagine the diameter of each circle being perpendicular to the stretched out conveyor belt in the form of a rectangle... The distance between the centers of the 2 circles will be length of the arm of the rectangle:
15 - (pie/2 + pie/2) = 15 - pie --- which will be sum of the 2 lengths of the rectangle
Since the lengths are equal --- the lenght of each arm aka the distance b/w the centers will be 15 - pie / 2
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
