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11 Sep 2025, 01:44
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D
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Difficulty:
25%
(medium)
Question Stats:
80% (02:32) correct
20%
(02:47)
wrong
based on 92
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Binu has n number of marbles with him, out of which he gives 1/5th of the marbles to Ramu, then he gives 2/3rd of the remaining marbles to Gaku, and is left with 12 marbles. Find the ratio of the number of marbles with Binu at the beginning and the total number of marbles with Ramu and Gaku.
A. 15:9
B. 15:8
C. 15:7
D. 15:11
E. 15:10
A. 15:9
B. 15:8
C. 15:7
D. 15:11
E. 15:10
12 Sep 2025, 10:10
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Naseeb007
Let \(n\) be the marbles with him initially. He gives \(\frac{1}{5}\) to Ramu hence is left with \(\frac{4}{5}\) of \(n,\) of this he gives \(\frac{2}{3}\) to Gaku, hence finally he has left:
\(\frac{1}{3} * \frac{4}{5}*n =12 \)
\(n=45\)
Thus he gives Ramu \(\frac{1}{5}*45 = 9\)
He gives Gaku \(\frac{1}{3} *36 = 12 \)
Required Ratio = \(\frac{45}{9+12} = \frac{15}{11} \)
Ans D
Hope it helped.
12 Sep 2025, 21:22
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To keep it simple, Assume Binu has 15x at the start. This is to avoid fractions.
So Ramu gets 3x, Gaku gets 2/3*12x => 8x
So remaining is 4x => 12. So x=3. Hence total at start are 45. An with Ramu and Gakue 33.
IMO 15:11.
So Ramu gets 3x, Gaku gets 2/3*12x => 8x
So remaining is 4x => 12. So x=3. Hence total at start are 45. An with Ramu and Gakue 33.
IMO 15:11.
