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22 May 2008, 01:20
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Friends, please help me justify the OA
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22 May 2008, 01:48
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Following the question:
3 notepads of the same size and same color -> for 4 diff colors, you can pack them in 4 different packs -> for two sizes you will get 8 different packs
using 4C3 -> for the same size different colors, you can pick 4 different ways thus for two sizes
4*2 =8
thus 16
3 notepads of the same size and same color -> for 4 diff colors, you can pack them in 4 different packs -> for two sizes you will get 8 different packs
using 4C3 -> for the same size different colors, you can pick 4 different ways thus for two sizes
4*2 =8
thus 16
22 May 2008, 03:57
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There are 2 same sized and 4 different colored pads.
Now we need to compute the number of cases where 1. all the 3 sizes are equal and all 3 colors are equal = 2X4 X 1X1 1X1 (chose 1 size out of 2 and 1 color out of 4)
2. 3 same sizes with 3 diff colors also, note that order does not matter so = 2X4 X 1X3 X 1X2 / 3! (3!) is because order doesnt matter.
Thus the sum is : 16
Now we need to compute the number of cases where 1. all the 3 sizes are equal and all 3 colors are equal = 2X4 X 1X1 1X1 (chose 1 size out of 2 and 1 color out of 4)
2. 3 same sizes with 3 diff colors also, note that order does not matter so = 2X4 X 1X3 X 1X2 / 3! (3!) is because order doesnt matter.
Thus the sum is : 16
