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12 Jun 2008, 08:56
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Attachment:
prep.doc
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12 Jun 2008, 10:45
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I think answer should be B.
Number in 1993 = 1000
Number in 1994 = 1000 + 1000*x/100 = 1000 + 10x
Number in 1995 = 1000 + 10x + (1000 + 10x)*y/100 = 1000 + 10(x+y) + xy/10
Statement 1:
Tells us XY = 20. Now there is various possible combinations for this (1,20),(2,10),(4,5) and each one of them will yield different result, so not sufficient.
Statement 2:
Tells us x + y + xy/100 = 9.2 => 10(x+y) + xy/10 = 92. So sufficient.
Answer B.
Number in 1993 = 1000
Number in 1994 = 1000 + 1000*x/100 = 1000 + 10x
Number in 1995 = 1000 + 10x + (1000 + 10x)*y/100 = 1000 + 10(x+y) + xy/10
Statement 1:
Tells us XY = 20. Now there is various possible combinations for this (1,20),(2,10),(4,5) and each one of them will yield different result, so not sufficient.
Statement 2:
Tells us x + y + xy/100 = 9.2 => 10(x+y) + xy/10 = 92. So sufficient.
Answer B.
12 Jun 2008, 16:37
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B.
I agree with Mr. Sen
I agree with Mr. Sen
Archived Topic
Hi there,
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Thank you for understanding, and happy exploring!
