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Updated on: 29 Apr 2007, 10:37
Originally posted by nervousgmat on 28 Apr 2007, 15:32.
Last edited by nervousgmat on 29 Apr 2007, 10:37, edited 1 time in total.
Last edited by nervousgmat on 29 Apr 2007, 10:37, edited 1 time in total.
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Please help me understand this question. I guessed on this one, and not sure why the correct answer is C.
Thanks!
Thanks!
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A = 2a
1/2*S*H = 2*1/2*s*h
S*H = 2*s*h
But, H/h = S/s. So,
S^2 = 2*s^2
So, S = s(2)^1/2
1/2*S*H = 2*1/2*s*h
S*H = 2*s*h
But, H/h = S/s. So,
S^2 = 2*s^2
So, S = s(2)^1/2
29 Apr 2007, 09:02
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I found a theorem online that states:
"The areas of two similar triangles are proportional to the squares of any two homologous sides."
Here is another website that has examples:
https://www.mathwarehouse.com/geometry/similar/triangles/area-similar-triangles.php
But I still cannot arrive at the OA.
Maybe someone can find my mistake.
We know these triangles are similar because they have the same angles.
Since the area is 2:1, the ratio of the sides is sqrt(2):1...
So sqrt(2)*S=s1...
S=s1/sqrt(2)...
S=(sqrt(2)*s1)/2...
Answer: A
"The areas of two similar triangles are proportional to the squares of any two homologous sides."
Here is another website that has examples:
https://www.mathwarehouse.com/geometry/similar/triangles/area-similar-triangles.php
But I still cannot arrive at the OA.
Maybe someone can find my mistake.
We know these triangles are similar because they have the same angles.
Since the area is 2:1, the ratio of the sides is sqrt(2):1...
So sqrt(2)*S=s1...
S=s1/sqrt(2)...
S=(sqrt(2)*s1)/2...
Answer: A
