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22 Feb 2009, 15:51
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Quant again
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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22 Feb 2009, 18:00
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It is given, lines l and k passes thru the point (4,3). Let m1 and b1 be the slope and y intercept of line l and m2 and b2 be the sloe and y intercept of k. So we know =
3 = 4m1 + b1 ; 3 = 4m2 + b2. The question being asked is "Is product of the slopes negative ? ".
From stmt 2 : - product of y intercepts is negative ==> means ONLY one of b1 or b2 is we know that x intercept in general is is -b/m. So it is given that
(-b1/m1) (-b2/m2) > 0 ==> b1b2/m1m2 > 0. Here we can understand that product of slopes and product of y intercetps should be of the same sign. But we can't say whether the product is positive or negative. So insufficient.
Now combine both the clues -
From stmt1, product of y intercepts and product of slopes have the same sign.
From stmt2, product of y intercepts is negative.
Now we can conclude that product of slopes is negative. Because from stmt 1, we know that both the products are having the same sign.
IMO C.
3 = 4m1 + b1 ; 3 = 4m2 + b2. The question being asked is "Is product of the slopes negative ? ".
From stmt 2 : - product of y intercepts is negative ==> means ONLY one of b1 or b2 is we know that x intercept in general is is -b/m. So it is given that
(-b1/m1) (-b2/m2) > 0 ==> b1b2/m1m2 > 0. Here we can understand that product of slopes and product of y intercetps should be of the same sign. But we can't say whether the product is positive or negative. So insufficient.
Now combine both the clues -
From stmt1, product of y intercepts and product of slopes have the same sign.
From stmt2, product of y intercepts is negative.
Now we can conclude that product of slopes is negative. Because from stmt 1, we know that both the products are having the same sign.
IMO C.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
