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19 Jul 2009, 01:54
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Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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19 Jul 2009, 15:04
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x tons (10%) + y tons (2%) => z = x+y tons (5%)
hence x/y = constant (mixture property)
1) y = 10 > x can be calculated
2) z = 16 > y= 16-x ... can be calculated
hence D
hence x/y = constant (mixture property)
1) y = 10 > x can be calculated
2) z = 16 > y= 16-x ... can be calculated
hence D
19 Jul 2009, 20:15
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0.1x+0.2y = 0.5X .... 1
x+y=Z ..... 2
So we have two equations and three variables. if we know one of the variables then we can solve for the other two.
x+y=Z ..... 2
So we have two equations and three variables. if we know one of the variables then we can solve for the other two.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
