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At Capetown college out of the 400 students taking Psychology 101 received an average score of 76 on the final exam, and the scores had a normal distribution. The bottom 16 percent of scores will receive a failing grade. If 8 students receive a score of 97 or higher, what is the score at or below which student fail the course?
a.35 b.40 c.55 d.62 e.66
Okay I dont know the answer but here is the logic I used ......i dont think its correct help me where I am wrong
Mean=76 8 Students received 97 or higher P(x>97) = 8/400 P(X>97)=2% 100-2%=98% Since 98% of the values in the distribution lie within 3 standard deviation of the mean
Hence 97-3(s.d)=76 s.d=7
16% failed hence (100-16%)/2 = 42%+42%= 84% which lies between 1 standard deviation or 2 standard deviation for approximation i use 2
hence
76-2*7= 62 ( I subtract cause its about failing )
what do you all say? some say answer is 66?
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8 students scoring 97 that means, 8/400 * 100 = 2% and mean is 76 = (97-x)/2 152 = 97-x x = 55 , i.e. two deviations away from mean i.e. 2 dev = (76-55)/2 and 1 dev = 10 appx 16 % fail = 84 % pass i.e. one deviation less than mean i.e. 76-10 = 66, Hence E
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