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29 Apr 2007, 02:20
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Hardsoft Ltd. has three divisions, each staffed by at least 10 people. The ratio of men to women is 7:5 in Finance and Administration, 3:4 in Marketing and Sales and 8:7 in Research and Development. If every Hardsoft employee works for exactly one of the three divisions, are there fewer than 120 women working in Hardsoft?
(1) There are 100 men working in Hardsoft.
(2) More women work in Finance and Adminstration than in Research and Development.
(1) There are 100 men working in Hardsoft.
(2) More women work in Finance and Adminstration than in Research and Development.
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29 Apr 2007, 08:06
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E for me too..there is no way of knowing the ratio to total number of men or women..
i mean each ratio is exactly that a ratio between men and women in a dept..have no idea how many there are over all in the company..
i mean each ratio is exactly that a ratio between men and women in a dept..have no idea how many there are over all in the company..
29 Apr 2007, 15:27
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(1) There´s a limited # of combinations of employees per dept if the # of men is exactly 100. In such case, given that the q is asking whether the # of women is less than 120, we push that variable to its highest, that is, we try to find the combination such that the # of women is maximized.
The ratio of men to women that can help us the most is 3:4. Let´s see, 99:132? what about the other depts? we need to have > =10 ppl in each dept, so we reduce the numbers to 96:128 (still too much), 93:124 (ok, let´s decrease it much further), 78:104. With this ratio: (7:5)*2 + (78:104) +(8:7) = 100:121, thus the # of women is >100.
Another possibility: 6*(7:5) + 6*(3:4) + 5*(8:7) = 100:89, thus # of women is less than 100.
Therefore (1) is not suff; B, C or E.
(2) Insuff right away.
(1&2) For 6*(7:5) + 14*(3:4) + 2*(8:7) = 100:100. As in the 1st case, the # of men is 100, but now the # of women is less than 100, therefore (1&2) is insuff and the answer is E.
The ratio of men to women that can help us the most is 3:4. Let´s see, 99:132? what about the other depts? we need to have > =10 ppl in each dept, so we reduce the numbers to 96:128 (still too much), 93:124 (ok, let´s decrease it much further), 78:104. With this ratio: (7:5)*2 + (78:104) +(8:7) = 100:121, thus the # of women is >100.
Another possibility: 6*(7:5) + 6*(3:4) + 5*(8:7) = 100:89, thus # of women is less than 100.
Therefore (1) is not suff; B, C or E.
(2) Insuff right away.
(1&2) For 6*(7:5) + 14*(3:4) + 2*(8:7) = 100:100. As in the 1st case, the # of men is 100, but now the # of women is less than 100, therefore (1&2) is insuff and the answer is E.
