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If a car is travelling at 60 km/h from A to B and then 100km/h from B to A what is his average speed for the trip?
I understand i can use the harmonic mean to solve this. \(2/(\frac{1}{60}+\frac{1}{100})= 75km/h\)
but how do we use alligations to solve this? or the seesaw method?
I can calculate the ratio of the times if I was given 75, but i mean this is a weighted average question of sorts right? We should be able to use the technique to, but I can't figure out how.
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Everything you're saying is correct - average speed is a kind of weighted average, weighted by the time you spend at each speed. But I would not suggest trying to use weighted average methods for average speed problems, for two reasons. For one, you normally aren't given the information you'd like to have, if you were going to use weighted average methods. Usually you're given distance information, and what you really want is information about time. And second, sometimes people get confused about what is responsible for the weighting (it can be easy to think it's the ratio of the distances that matters, rather than the ratio of times), and if you don't use the correct weights, you'll get the wrong answer.
Here, the distances are equal. So the ratio of the times spent will be d/60 to d/100, or 1/60 to 1/100, and multiplying by 300 to get integers, will be 5 to 3. Since more time is spent at 60 mph, the answer will be closer to 60. Using alligation (if anyone reading this is unfamiliar with "alligation", this likely won't make sense), we have:
---60-------A--------------100---
and the ratio of the distances to the middle average must be 3 to 5, so the smaller distance on the left is 3/8 of the entire distance between 60 and 100, so is (3/8)(40) = 15, and A = 60 + 15 = 75.
I use alligation all the time, but I'd just solve this problem, and most other average speed problems, using an average speed table, since that turns out to be easier most of the time. This is, however, the only kind of weighted average problem that shows up on the GMAT where I would avoid alligation.
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Hi there,
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