This can be solved by setting up two equations concerning the total number of pages.
Let him read p pages per day initially and let it take d days for him to finish reading. So the total number of pages is pd.
\(pd = 480\) (1)
In the other condition stated, it says that he could have finished the book 5 days earlier if he had read 16 more pages per day.
This means that he reads (p+16) pages per day and it takes him (d-5) days to finish the book. The total number of pages in this case is (p+16)(d-5).
But note that this is the same as the total number of pages hasn't changed.
\((p+16)(d-5) = 480\)
Expanding this we get: \(pd - 5p + 16d - 80 = 480\) (2)
Substituting (1) into (2) in place of pd, we get:
\(480 - 5p + 16d - 80 = 480\)
\(16d - 5p = 80\)
Now we can substitute \(p = \frac{480}{d}\) into this equation to get the following quadratic:
\(16d - \frac{2400}{d} = 80\)
\(16d^2 - 80d - 2400 = 0\)
Dividing by 16 throughout
\(d^2 - 5d - 150 = 0\)
\(d^2 - 15d + 10d - 150 = 0\)
\((d-15)(d+10) = 0\)
\(d = 15\) or \(-10\)
But d, being the number of days, cannot be negative. Hence d = 15 is the answer. Answer choice C.
Hope this helps.