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Help Needed Prep Question

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Director
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Help Needed Prep Question [#permalink]

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New post 18 Jul 2009, 09:00
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Kudos [?]: 628 [0], given: 2

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Re: Help Needed Prep Question [#permalink]

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New post 18 Jul 2009, 12:01
I got this questions while doing the simulation as well.

This is what I did.

The first part of the equation, \((-1)^k+1\), will only determine whether the number is positive or negative.

For k = 1, this part will be 1
For k = 2, this part will be -1
For k = 3, this part will be 1, again. Thus, when k is even the term will be multiple by -1, and it will be negative. However, when k is odd the term will be positive.

The second part of the equation just tell us that is a fraction of power of 2.

Thus the numbers are:

\(1/2, -1/4, 1/8, -1/16, 1/32, -1/64, 1/128, -1/256, 1/512, -1/1024\)

Now try to sum the first positives to have a impression of the sum of the positives, and do the same with the negatives.

If you transform them to decimal, you will notice that the first positives, are, 0.5, 0.125, 0.03, now hold on. The sum here is 0.655. The way the numbers are going down to fast, you can see that this sum will not pass 0.7, or if it pass, it will be very close to 0.7. Save this number.

Now, if you sum the negatives, in decimal, you will see -0.25, -0.06, ok that is enough. You do not need even to continue. As you can see, again the numbers are going down ("modularity talking") so fast that you can see the the sum will be around -0.3.

Thus \(0.7 - 0.3 =~ 0.4\), your answer approximately.

D between 0.25 and 0.5

Kudos [?]: 96 [0], given: 13

Re: Help Needed Prep Question   [#permalink] 18 Jul 2009, 12:01
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