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Bunuel
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study4job
Is 5^n < 0.04?

(1) (1/5)^n > 25

(2) n^3 < n^2


Given \(5^n < 0.04\)
\(5^n < 0.04 ( 0.04=4/100=1/25=5^{-2 }\)
\(n<-2 ?\)

option A:
\(5^{- n} > 25=5^2\) ; implies n<-2 SUFFICIENT
option B:

\(n^3 < n^2 \\
==> n^3-n^2 <0 \\
==> n^2(n-1) <0 \\
==> n-1<0 \\
==> n<1\) NOT SUFFICIENT.

Bunuel , have i solved the second inequality incorrectly ?

thanks
lucky
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Lucky2783
study4job
Is 5^n < 0.04?

(1) (1/5)^n > 25

(2) n^3 < n^2


Given \(5^n < 0.04\)
\(5^n < 0.04 ( 0.04=4/100=1/25=5^{-2 }\)
\(n<-2 ?\)

option A:
\(5^{- n} > 25=5^2\) ; implies n<-2 SUFFICIENT
option B:

n^3 < n^2
==> n^3-n^2 <0
==> n^2(n-1) <0
==> n-1<0
==> n<1 NOT SUFFICIENT.

Small correction: for (2) it should be n < 0 or 0 < n < 1. 0 must be excluded, because for n = 0, n^3 < n^2 does not hold true.
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Bunuel
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study4job
Is 5^n < 0.04?

(1) (1/5)^n > 25

(2) n^3 < n^2


Given \(5^n < 0.04\)
\(5^n < 0.04 ( 0.04=4/100=1/25=5^{-2 }\)
\(n<-2 ?\)

option A:
\(5^{- n} > 25=5^2\) ; implies n<-2 SUFFICIENT
option B:

n^3 < n^2
==> n^3-n^2 <0
==> n^2(n-1) <0
==> n-1<0
==> n<1 NOT SUFFICIENT.

Small correction: for (2) it should be n < 0 or 0 < n < 1. 0 must be excluded, because for n = 0, n^3 < n^2 does not hold true.


got it Bunuel . i missed it. thanks so much .
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Here is my approach:

Statement 1:
\(\frac{1}{5}^n > 25\)
\(5^-n > 5^2\)
\(-n > 2\)
\(n < -2\)

plug in n=-3 into the equation will yield that 1/125 is < than 0,04

Sufficient

Statement 2:
per statement n can be either a negative number or a proper fraction. 5^(1/2) would be > 0,04 while to a negative power would be <. not sufficient.

--> A
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Bunuel

Tough and Tricky questions: Absolute Values.



Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2


Hi gmatbusters, Can you please share your thoughts on inline approach.

Is this a validate approach ??

is 5^n < 5^-2
becomes is n < -2 ??

1) 5^(-n) > 5^2
=> -n > 2
=> n < -2
Sufficient

2) Can't tell anything from this.
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Hii

Your approach to use first statement is correct.

For second statement.
n^3 < n^2
n^2(n-1)<0
n < 1
But since now n can be < or > -2, statement 2 is not sufficient

Hence Answer - A

KanishkM
Bunuel

Tough and Tricky questions: Absolute Values.



Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2


Hi gmatbusters, Can you please share your thoughts on inline approach.

Is this a validate approach ??

is 5^n < 5^-2
becomes is n < -2 ??

1) 5^(-n) > 5^2
=> -n > 2
=> n < -2
Sufficient

2) Can't tell anything from this.
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Bunuel

Tough and Tricky questions: Absolute Values.



Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2

Question : Is \(5^n < 0.04\) ?

Or Is \(5^n < \frac{4}{100}\) ?

Or Is \(5^n < 5^{-2}\) ?

Finally, Is \(n < -2\) ?

Statement 1 : \(\frac{{1^n}}{{5}^n} > 25\)

Or 5\(^{-n} > 5^2\)

Or \(-n > 2\)

Or \(n < -2\) (Answer to the question, YES) SUFFICIENT

Statement 2 :

\(n^3 < n^2\) (As \(n^2\) will always be positive, divide both sides by n^2)

We get, n < 1

If \(n = 0\), the answer to the question is NO

If \(n = - 3\), the answer to the question is YES

NOT SUFFICIENT
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Pretty tricky.

Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2

The question is asking 5^n < 0.04? This is the same as 5^n < 5^-2? In other words, is n less than -2?

(1) (1/5)^n > 25 ----> 5^-n > 5^2 ---> -n > 2 ---> n < -2
Sufficient.

(2) n^3 < n^2
n^3 - n^2 < 0
n^2 (n - 1) < 0 ---> Implies that n is negative, but n can be -1, -2, -3...Each of these satisfies the inequality.
Insufficient.
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