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Hot tea at a temperature of 60˚ and cold water at a temperature of 10˚ are added to 50 mL of lemon juice at room temperature (25˚). The resulting mixture has a temperature of 40˚. How much hot tea was added?
(1) The tea and water were added in a 2:1 ratio.
(2) The mixture has a volume of 275 mL
(1) The tea and water were added in a 2:1 ratio.
(2) The mixture has a volume of 275 mL
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15 Jul 2006, 02:17
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A) the mixture will have 650/15=43,3 degrees temperature.
The equation is (X*43,3)/(X+50)+50*25/(X+50)=40 and we can find how many ml of the tea is added
B) We can find the temperature of the added mixture and from there the amount of tea
IMO D
The equation is (X*43,3)/(X+50)+50*25/(X+50)=40 and we can find how many ml of the tea is added
B) We can find the temperature of the added mixture and from there the amount of tea
IMO D
15 Jul 2006, 02:31
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D
Stem: 60T+10W+50*25 = (T+W+50)*40
St1: T = 2W. We can solve two equations for T and W. We get T = 50ml and W = 25ml: SUFF
St2: T + W + 50 = 300 i.e T+W = 250. We can solve two equations for T and W. We get T = 199 and W = 51: SUFF
But generally we don't get different answers in GMAT. Is my solution correct or not???
Stem: 60T+10W+50*25 = (T+W+50)*40
St1: T = 2W. We can solve two equations for T and W. We get T = 50ml and W = 25ml: SUFF
St2: T + W + 50 = 300 i.e T+W = 250. We can solve two equations for T and W. We get T = 199 and W = 51: SUFF
But generally we don't get different answers in GMAT. Is my solution correct or not???
