How do you reduce the following problems? I'm fine until I

Question

How do you reduce the following problems? I'm fine until I start adding in the 5s in front of the x's.

(5x^-3)^-3 


(5x^-3)^3 


(-5x^-3)^-3


(-5x^-3)^3

bsd_lover · Answer

1) (5x^-3)^-3 
 = 5^-3 * x^(-3 * -3)
 = x^9 / 125 (since 5^-3 is the same as 1/(5^3)

2) (5x^-3)^3 
 = 125 / (x^9) --> see above as to why they are now swapped around

3) (-5x^-3)^-3 
 = -x^9 / 125 (since -5^-3 is -1/5^3 )

4) (-5x^-3)^3
 = -125/(x^9)

Hope I am right in all of these I am verryyy sleepy atm.
Give us a yell if you have any other exponents questions.

skinsvt · Answer

Thanks

One more question. If we were to add a y^3 after the x^3 in all of the equations

Would we have 5^3 * x^3* y*3 or would we reduce it in a different way.

bsd_lover · Answer

Lets see :
(5*x^-3*y^3)^-3 
This will then reduce to
5^-3*x^(-3*-3)*y^(3*-3)
x^9/(5^3*y^9)

Is this what you mean ?

skinsvt · Answer

Yep..exactly...Appreciate the help..Just wanted to make sure as you add more variables the formula stays the same

bsd_lover · Answer

Yup no problem.

(x*y*z)^2 is same as x^2*y^2*z^2

shahrukh · Answer

The rule is very simple.
(xy)^2= x^2*y^2 or
(5xy)^2 = 5^2*x^2*y^2
in simple words, when things are being multiplied and they ahve a combined power, then that combine dpower is indeed each one's individual power.
power=exponent
hope this helps

How do you reduce the following problems? I'm fine until I

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