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16 Nov 2006, 16:33
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How do you set up equations for X overtaking Y or X meeting up with Y.
X speed 50m/h, Y speed 60m/h
x leaves at 1am, Y leaves at 2am
I make a table - but would like to figure how to solve via equations
here's what I do
2am 3am 4am 5am 6am 7am 8am
X 50 100 150 200 250 300 350
Y 0 60 120 180 240 300 360
at 7am parallel and 8am y overtaken X. Is there a grown up way to do this? :-D
X speed 50m/h, Y speed 60m/h
x leaves at 1am, Y leaves at 2am
I make a table - but would like to figure how to solve via equations
here's what I do
2am 3am 4am 5am 6am 7am 8am
X 50 100 150 200 250 300 350
Y 0 60 120 180 240 300 360
at 7am parallel and 8am y overtaken X. Is there a grown up way to do this? :-D
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17 Nov 2006, 00:38
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X train: rate=50, time=t, distance=d-50 (since the x train has started earlier and travelled 50 km)
Y train: r=60 time=t distance=d
Construct two equations:
r*t=d
50t=d-50 (1)
60t=d (2) include this into (1) equation
50t=60t-50
50t-60t=-50
-10t=-50
t=5
After 5 hours train Y will catcth up with train X... or at 7 am.
Y train: r=60 time=t distance=d
Construct two equations:
r*t=d
50t=d-50 (1)
60t=d (2) include this into (1) equation
50t=60t-50
50t-60t=-50
-10t=-50
t=5
After 5 hours train Y will catcth up with train X... or at 7 am.
17 Nov 2006, 05:00
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Hi successstory. SimaQ's way is good, but if you need more help with rate problems I found this site useful. I also used to do it the kiddie way.
https://www.webmath.com/Wordp/menu_rate.html :wink:
I think you would use #10 on this site for the problem you posted.
https://www.webmath.com/Wordp/menu_rate.html :wink:
I think you would use #10 on this site for the problem you posted.
