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stoolfi
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is this the optimum approach dj? Aren't you solving potentially 3 questions to come up with the ans for a 4th one?

Also I did not understand "left us with 4000 " .. you are saying total = 8000; first two cases sum up to 5000 .. so ..?

my approach ...
first digit can be any of 4 = 2,4,6,8
2nd and 3rd = 10 each
4th can be any of 5 = 1,3,5,7,9

total = 4 * 10 * 10 * 5 = 2000

Stoolfi's approach (explained in another problem of the same type) is probably much faster for similar problems for GMAT

Any thoughts?
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stoolfi
How many 4-digit numbers begin with an even digit and end
with an odd digit?

A 2000
B 2001
C 2499
D 2500
E 2501



10 digits... 5 even and 5 odd

first digit can be selected in 4 ways ( 0 cant be considered)

second and third in 10 ways each ...

the fourth in 5 ways

total = 4*10*10*5 = 2000



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