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# How many committees of 3 men and 4 women can be made when choosing fro

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Math Expert
Joined: 02 Sep 2009
Posts: 52161
How many committees of 3 men and 4 women can be made when choosing fro  [#permalink]

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13 Dec 2016, 06:26
1
00:00

Difficulty:

5% (low)

Question Stats:

98% (01:22) correct 3% (00:37) wrong based on 58 sessions

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How many committees of 3 men and 4 women can be made when choosing from 8 men and 7 women?

A. 6435
B. 1960
C. 672
D. 392
E. 156

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Senior Manager
Joined: 13 Oct 2016
Posts: 367
GPA: 3.98
How many committees of 3 men and 4 women can be made when choosing fro  [#permalink]

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13 Dec 2016, 07:02
1
$$_8C_3 *_7C_4 = \frac{8*7*6}{3*2} * \frac{7*6*5}{3*2} = 56*35 = 1960$$

Director
Joined: 24 Nov 2015
Posts: 515
Location: United States (LA)
Re: How many committees of 3 men and 4 women can be made when choosing fro  [#permalink]

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19 May 2017, 06:42
3 men can be selected from 8 men in 8C3 ways = 56 ways
4 women can be selected out of 7 women in 7C4 ways = 35 ways
Total number of ways of selection = 56 * 35 = 1960
Senior Manager
Joined: 13 Oct 2016
Posts: 283
GMAT 1: 600 Q44 V28
How many committees of 3 men and 4 women can be made when choosing fro  [#permalink]

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19 May 2017, 06:59
Here the very first thing we have to figure out if we have to choose the permutation approach or the combination approach.

Whenever selection is done we apply the combination method.

Whenever arrangement is done we apply permutation method.

Here since the question talks about choosing(Selection) men and women from a community we have to proceed ahead with combination method.

Therefore , 8C3*7C4 = [(8*7*6)/(3*2*1)] * [(7*6*5)/(3*2*1)] = 1960 .

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How many committees of 3 men and 4 women can be made when choosing fro &nbs [#permalink] 19 May 2017, 06:59
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