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How many committees of 3 men and 4 women can be made when choosing fro

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How many committees of 3 men and 4 women can be made when choosing fro [#permalink]

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New post 13 Dec 2016, 06:26
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A
B
C
D
E

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Question Stats:

95% (00:55) correct 5% (00:18) wrong based on 49 sessions

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Senior Manager
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How many committees of 3 men and 4 women can be made when choosing fro [#permalink]

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New post 13 Dec 2016, 07:02
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\(_8C_3 *_7C_4 = \frac{8*7*6}{3*2} * \frac{7*6*5}{3*2} = 56*35 = 1960\)

Answer B
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Re: How many committees of 3 men and 4 women can be made when choosing fro [#permalink]

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New post 19 May 2017, 06:42
3 men can be selected from 8 men in 8C3 ways = 56 ways
4 women can be selected out of 7 women in 7C4 ways = 35 ways
Total number of ways of selection = 56 * 35 = 1960
Correct Answer - B
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How many committees of 3 men and 4 women can be made when choosing fro [#permalink]

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New post 19 May 2017, 06:59
Here the very first thing we have to figure out if we have to choose the permutation approach or the combination approach.

Whenever selection is done we apply the combination method.

Whenever arrangement is done we apply permutation method.

Here since the question talks about choosing(Selection) men and women from a community we have to proceed ahead with combination method.

Therefore , 8C3*7C4 = [(8*7*6)/(3*2*1)] * [(7*6*5)/(3*2*1)] = 1960 .

Hence answer is option B.
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How many committees of 3 men and 4 women can be made when choosing fro   [#permalink] 19 May 2017, 06:59
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How many committees of 3 men and 4 women can be made when choosing fro

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