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Bunuel
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Tricky one!
Volume information isnt efficient unless we know atleast two dimensions about box. hence 1st not sufficient.
2nd- Length greater than and equal to width and height. means both height and widhth are max can go upto 3. hence it is sufficient. because as per these diemension limits cans cant fit in the box.
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stne

Bunuel
How many cylindrical cans with a radius of 2 inches and a height of 6 inches can fit into a rectangular box?

(1) The volume of the box is \(230 \) cubic inches
(2) The length of the box is \(3 \) inches

(1) The volume of the box is \(230\) cubic inches

This statement is clearly INSUFF. as there can be various combinations of L*B*H hence different number of cylindrical cans can be accomodated.

(2) The length of the box is \(3\) inches

Longest portion of the box i.e. length, is \(3\) inches which means all other sides i.e. width and height are either \(3\) or less than \(3\). Which means the CAN's that have a diameter of \(4\) inches and height of \(6\) inches CANNOT fit in the box in any kind of position. Hence the answer is ZERO number of CANS.

SUFF.

Ans B

Hope it's clear.
 
­

Is it some sort of a rule that length has to be the longest side out of the 3?
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