This is our solution to this question.
Solution: Step 1: Understand Question Stem: We are asked the number of factors of 2^3×3^2×5^5 that are multiples of 12
Step 2: Define Methodology: Firstly, we have to express the number as \(12 × Something\).
To do that we can divide the given number \(2^3×3^2×5^5\) by 12
We will get \( \frac{(2^3×3^2×5^5)}{12}=\frac{(2^3×3^2×5^5)}{(2^2×3)}=2^1×3^1×5^5 \)
So, we have \(2^3×3^2×5^5 = 12 × (2^1×3^1×5^5)\)
Now, we just need to find the total number of factors of \(2×3×5^5\) to find out our answer.
The logic is simple because every factor of \(2×3×5^5\) will eventually be multiplied by 12 and become a multiple of 12 and the factor of the original number \(2^3×3^2×5^5\).
Step 3: Calculate the Final Answer: We have \(\frac{(2^3×3^2×5^5)}{12}=\frac{(2^3×3^2×5^5)}{(2^2×3)}=2^1×3^1×5^5\)
Total number of factors of \(2^1×3^1×5^5\)\(=(1+1)×(1+1)×(5+1)=2×2×6=24 \)
Hence the right answer is
Option D. Note:This question is created to test the knowledge related to the number of factors of a number. We have published an article can on the same. You can view it using this
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