Can you tell my why I'm wrong?

Even numbers are 0,2,4,6,8

Odd numbers are 1,3,5,7,9

# of five digit numbers w/o 4 = 3*4*5*5*5 = 1500

- w/o 4, I'd get = 4*4*5*5*5# of five digit numbers w/ 4 as first digit = 1*4*5*5*5 = 500

For this, I get 1*4*5*5*5# of five digit number w/ 4 as second digit = 3*1*5*5*5 = 375

For this, I get 4*1*5*5*5zoinnk wrote:

Nihit wrote:

. How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number?

a) 1875

b) 2000

c) 2375

d) 2500

e) 3875

C

# of five digit numbers w/o 4 = 3*4*5*5*5 = 1500

# of five digit numbers w/ 4 as first digit = 1*4*5*5*5 = 500

# of five digit number w/ 4 as second digit = 3*1*5*5*5 = 375

Total = 1500+500+375