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Difficulty:
35%
(medium)
Question Stats:
61% (00:56) correct
39%
(01:07)
wrong
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How many integers n are there such than v < n < w ?
(1) v and w are positive integers.
(2) w - v = 4
(1) v and w are positive integers.
(2) w - v = 4
How many integers n are there such that v<n<w?
(1) v and w are positive integers?
(2) w-v=4
How is it even possible that v<w when v-w=4?
from gmathacks
(1) v and w are positive integers?
(2) w-v=4
How is it even possible that v<w when v-w=4?
from gmathacks
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
14 Mar 2012, 06:33
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BN1989
(2) should read: w-v=4.
How many integers n are there such that v<n<w?
Notice that if \(w\) and \(v\) are integers, for example \(w=5\) and \(v=1\) then there will be 3 integers between them: 2, 3, and 4. But if \(w\) and \(v\) are NOT integers for example \(w=5.5\) and \(v=1.5\) then there will be 4, so one more, integers between them: 2, 3, 4 and 5.
(1) v and w are positive integers. Not sufficient.
(2) w-v=4. Not sufficient.
(1)+(2) According to above reasoning since v and w are positive integers then there are 3 integers between them (case 1). Sufficient.
Similar question to practice: how-many-integers-n-are-there-such-that-r-n-s-101917.html
Hope it helps.
17 Mar 2012, 05:21
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BN1989
The question stem seems to ask how many integral triplets exists which are bound by v<n<w?
Whereas the intent is to ask how many integral values of n exist such that v<n<w ?
Only if we are interested in finding the no. of integral values n can take then we can get the answer
by combining 1&2 (as Bunnel stated)
But if we are interested in finding integers then obeying 1&2 we can take any natural no. as v and accordingly our w will get fixed and then we can choose any 3 no.s between w and v to get n.So infinite no. of triplets can be formed.
@Bunnel: I would be thankful if you clarify
