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25 Nov 2019, 23:12
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How many integers of x are there so that \(x + 3 < 1 < 2x + 9\) ?
(A) Four
(B) Three
(C) Two
(D) One
(E) None
25 Nov 2019, 23:33
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How many integers of x are there so that x+3<1<2x+9 ?
(A) Four
(B) Three
(C) Two
(D) One
(E) None
x+3 < 1 & 1 < 2x+9
x < -2 & x > -4
Only -3 satisfies both.
Answer D.
(A) Four
(B) Three
(C) Two
(D) One
(E) None
x+3 < 1 & 1 < 2x+9
x < -2 & x > -4
Only -3 satisfies both.
Answer D.
25 Nov 2019, 23:39
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x+3 < 1 < 2x+9
--> x + 3 < 1 and 2x + 9 > 1
--> x < 1 - 3 & 2x > -8
--> x < -2 & x > - 4
--> -4 < x < -2
So, only possible value of x = -3 --> One possible value
IMO Option D
--> x + 3 < 1 and 2x + 9 > 1
--> x < 1 - 3 & 2x > -8
--> x < -2 & x > - 4
--> -4 < x < -2
So, only possible value of x = -3 --> One possible value
IMO Option D
