Bunuel
How many liters of 20% vinegar solution should be added to 4 liters of 50% vinegar solution to make a 30% vinegar solution?
A. 1
B. 2
C. 4
D. 6
E. 8
Using weighted averages:
\(\frac{w1}{w2} = \frac{(A2 - Avg)}{(Avg - A1)}\)
\(\frac{w1}{w2 }= \frac{(50 - 30)}{(30 - 20)} = \frac{2}{1}\)
Hence for every 2 parts of 20% solution we have 1 part of 50% solution.
Since we have 4 litres of 50% solution, we must have added 8 litres of 20% solution.
Answer (E)
Or we can use the scale method to visualise the answer:
20 ------30 ------------------- 50
Since distance is in the ratio 1:2, the weights will be in the ratio 2:1 for 20% and 50% solution respectively. Since we have 4 litres of 50% solution, we must have added 8 litres of 20% solution.
Check Weighted Avg and Mixtures Basics in these posts:
https://anaprep.com/arithmetic-weighted-averages/https://anaprep.com/arithmetic-mixtures/and these videos:
https://www.youtube.com/watch?v=_GOAU7moZ2Qhttps://www.youtube.com/watch?v=VdBl9Hw0HBg