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Bunuel
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Need both statements to solve. 1) any value of m and n can add to 20 so NS. 2) Could be any number so NS. Combined we only receive one set.
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why is B not sufficient ?
Doesnt it mean that number of men are twice the number of women , so we have an answer
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RB15
Let number of men = m and women = w

(1) m+n=20; not sufficient
(2) m = n^2; notsufficient

Together we arrive at the equation => n^2 + n =20; can be solved to give n and consequently m

Answer: C


1. M + W = 20

2. M = W ^2

only M =4 & W =4 Satisfying

C is correct
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Hey hsn81960,
How did you come to the conclusion that number of men are twice the number of women from statement 2?

From statement 2, number of men = Square of number of women.
But we do not know what the number of women so, we can not find number of men. Hence, we can not find how many men are more than women.

Hope this helps you.
Regards,
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Bunuel
How many more men than women are in the room?

(1) There is a total of 20 women and men in the room.
(2) The number of men in the room equals the square of the number of women in the room.

Statement 1: M+W=20
Statement 2: \(M=(W)^2\)

Combining both: M=16,W=4. So the answer is 12.

Hence C
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Bunuel
How many more men than women are in the room?

(1) There is a total of 20 women and men in the room.
(2) The number of men in the room equals the square of the number of women in the room.

Asked: How many more men than women are in the room?

(1) There is a total of 20 women and men in the room.
Since number of men and women are not known separately
NOT SUFFICIENT

(2) The number of men in the room equals the square of the number of women in the room.
m = w^2
If m=4; w=2
If m=9; w=3
NOT SUFFICIENT

Combining (1) & (2)
(1) There is a total of 20 women and men in the room.
(2) The number of men in the room equals the square of the number of women in the room.[/quote]
m+w=20
m=w^2
w^2+w-20=0
(w+5)(w-4)=0
w=4 or -5
w=4 since w=-5 is not feasible
m=4^2=16
m-w=15-4=12

IMO C
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