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How many multiples of 10 are there between 1000 and 2000, inclusive?

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How many multiples of 10 are there between 1000 and 2000, inclusive?  [#permalink]

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12 Aug 2010, 09:27
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How many multiples of 10 are there between 1000 and 2000, inclusive?

OA:
101

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Posts: 55236
Re: How many multiples of 10 are there between 1000 and 2000, inclusive?  [#permalink]

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12 Aug 2010, 09:44
Baten80 wrote:
How many multiples of 10 are there between 1000 and 2000, inclusive?

Let me to know the calculation process.
Ans.101

Hi, and welcome to Gmat Club! Below is a solution for your problem:

$$# \ of \ multiples \ of \ x \ in \ the \ range = \frac{Last \ multiple \ of \ x \ in \ the \ range \ - \ First \ multiple \ of \ x \ in \ the \ range}{x}+1$$.

For our original question we would have: $$\frac{2,000-1,000}{10}+1=101$$.

Check this: totally-basic-94862.html?hilit=last%20first%20range%20multiple

Hope it helps.
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Re: How many multiples of 10 are there between 1000 and 2000, inclusive?  [#permalink]

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12 Aug 2010, 09:47
1
My attempt:

1000 - 1100 -- 11
1110 - 1200 -- 10
1210 - 1300 -- 10

1X10 - 1(X+1)00 -- 10

X - 3, 4, 5, 6 ,7 ,8, 9.

Sum them up - 101.
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Re: How many multiples of 10 are there between 1000 and 2000, inclusive?  [#permalink]

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12 Aug 2010, 11:27
In general the formula for any series where "d" is the increment or difference between two terms to find the nth term =
An= A1+ (n-1)d
Now we know An =2000
A1=1000
d=10
2000=1000+(n-1)10
=101

OR
Use this
( last -first )/ increment + 1

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Re: How many multiples of 10 are there between 1000 and 2000, inclusive?  [#permalink]

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14 Aug 2010, 09:44
As already discussed, the method is [(Last-First)/Increment ]+1

If you are refering to mgmat by any chance, this is discussed in Chap4 of Number properties
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Re: How many multiples of 10 are there between 1000 and 2000, inclusive?  [#permalink]

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06 Sep 2017, 22:57
Bunuel wrote:
Baten80 wrote:
How many multiples of 10 are there between 1000 and 2000, inclusive?

Let me to know the calculation process.
Ans.101

Hi, and welcome to Gmat Club! Below is a solution for your problem:

$$# \ of \ multiples \ of \ x \ in \ the \ range = \frac{Last \ multiple \ of \ x \ in \ the \ range \ - \ First \ multiple \ of \ x \ in \ the \ range}{x}+1$$.

For our original question we would have: $$\frac{2,000-1,000}{10}+1=101$$.

Check this: http://gmatclub.com/forum/totally-basic ... 20multiple

Hope it helps.

Hi Bunuel, Thanks for the explanation. However, if the question would have been that how many multiples of 5 are there between -7 and 37, inclusive? Will we consider the last number to be 35 and the first number to be -5?
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Joined: 02 Sep 2009
Posts: 55236
Re: How many multiples of 10 are there between 1000 and 2000, inclusive?  [#permalink]

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06 Sep 2017, 23:07
SinhaS wrote:
Bunuel wrote:
Baten80 wrote:
How many multiples of 10 are there between 1000 and 2000, inclusive?

Let me to know the calculation process.
Ans.101

Hi, and welcome to Gmat Club! Below is a solution for your problem:

$$# \ of \ multiples \ of \ x \ in \ the \ range = \frac{Last \ multiple \ of \ x \ in \ the \ range \ - \ First \ multiple \ of \ x \ in \ the \ range}{x}+1$$.

For our original question we would have: $$\frac{2,000-1,000}{10}+1=101$$.

Check this: http://gmatclub.com/forum/totally-basic ... 20multiple

Hope it helps.

Hi Bunuel, Thanks for the explanation. However, if the question would have been that how many multiples of 5 are there between -7 and 37, inclusive? Will we consider the last number to be 35 and the first number to be -5?

How many multiples of 5 are there between -7 and 37, inclusive?

The first multiple is -5 and the last multiple is 35, so the answer is (35 - (-5))/5 + 1 = 9:
-5, 0, 5, 10, 15, 20, 25, 30 and 35.
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How many multiples of 10 are there between 1000 and 2000, inclusive?  [#permalink]

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06 Sep 2017, 23:11
Bunuel wrote:
SinhaS wrote:
How many multiples of 10 are there between 1000 and 2000, inclusive?

Let me to know the calculation process.
Ans.101

Hi, and welcome to Gmat Club! Below is a solution for your problem:

$$# \ of \ multiples \ of \ x \ in \ the \ range = \frac{Last \ multiple \ of \ x \ in \ the \ range \ - \ First \ multiple \ of \ x \ in \ the \ range}{x}+1$$.

For our original question we would have: $$\frac{2,000-1,000}{10}+1=101$$.

Check this: http://gmatclub.com/forum/totally-basic ... 20multiple

Hope it helps.

Hi Bunuel, Thanks for the explanation. However, if the question would have been that how many multiples of 5 are there between -7 and 37, inclusive? Will we consider the last number to be 35 and the first number to be -5?

How many multiples of 5 are there between -7 and 37, inclusive?

The first multiple is -5 and the last multiple is 35, so the answer is (35 - (-5))/5 + 1 = 9:
-5, 0, 5, 10, 15, 20, 25, 30 and 35.

Thanks. I got it right. Now it's clear.
How many multiples of 10 are there between 1000 and 2000, inclusive?   [#permalink] 06 Sep 2017, 23:11
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How many multiples of 10 are there between 1000 and 2000, inclusive?

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