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12 Feb 2020, 12:03
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how many integer 100-200 that are divisible by 2, 3, but not 5
|A1| number that divisible by 2= 101/2=50
|A2| number divisible by 3= 101/3=33
|A3|=number divisible by 5
|A1∩A3| divisible by 2 and 5=101/(2*5)=10
|A2∩A3| divisible by 3 and 5=101(3*5)=6
|A1∩A2∩A3|= divisible by 2 ,3, 5= 101/(2*3*5)= 3
|A1|+|A2|-(|A1∩A2| +|A2∩A3| )+|A1∩A2∩A3|= 50+33-(10+6)+3=70
is this right?
|A1| number that divisible by 2= 101/2=50
|A2| number divisible by 3= 101/3=33
|A3|=number divisible by 5
|A1∩A3| divisible by 2 and 5=101/(2*5)=10
|A2∩A3| divisible by 3 and 5=101(3*5)=6
|A1∩A2∩A3|= divisible by 2 ,3, 5= 101/(2*3*5)= 3
|A1|+|A2|-(|A1∩A2| +|A2∩A3| )+|A1∩A2∩A3|= 50+33-(10+6)+3=70
is this right?
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12 Feb 2020, 20:27
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i think what the question meant was how many integers between 100 and 200 and are divisible by both 2 and 3 but not by 5
in that scenario we should have taken numbers divisible by 6 but not by 5
that means
17 numbers are divisible by 6 out of which 3 are divisible by 5 also (6 and 5 i.e 30)
thus total number of numbers are 17-3 = 14
in that scenario we should have taken numbers divisible by 6 but not by 5
that means
17 numbers are divisible by 6 out of which 3 are divisible by 5 also (6 and 5 i.e 30)
thus total number of numbers are 17-3 = 14
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
