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02 Mar 2021, 10:00
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
46% (01:36) correct
54%
(01:22)
wrong
based on 160
sessions
History
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Time
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Not Attempted Yet
How many numbers greater than 4000 can be formed using the digits 3, 5, 7, 8, and 9 if the repetition of the digits is not allowed ?
A. 96
B. 120
C. 168
D. 192
E. 216
A. 96
B. 120
C. 168
D. 192
E. 216
02 Mar 2021, 10:13
Kudos
Bookmarks
We can have 4 digit numbers or 5 digit numbers
4 digit numbers: The first place cannot have 3. So we can have 4 numbers in the first place.
Then we can have 4 numbers (including 3 and excluding the number chosen in the first place) in the secon place, 3 numbers in the 3 place and any 2 numbers in the last place.
Total numbers possible = 4 * 4 * 3 * 2 = 96
5 digit numbers: All the numbers will be greater than 4000. We can have 5! = 120 numbers
Total numbers greater than 4000 = 96 + 120 = 216
Option E
Arun Kumar
4 digit numbers: The first place cannot have 3. So we can have 4 numbers in the first place.
Then we can have 4 numbers (including 3 and excluding the number chosen in the first place) in the secon place, 3 numbers in the 3 place and any 2 numbers in the last place.
Total numbers possible = 4 * 4 * 3 * 2 = 96
5 digit numbers: All the numbers will be greater than 4000. We can have 5! = 120 numbers
Total numbers greater than 4000 = 96 + 120 = 216
Option E
Arun Kumar
02 Mar 2021, 11:09
Kudos
Bookmarks
Number of 4 digit numbers that can be formed using the 5 different digits is
5P4 =120
Numbers greater than 4000 are the ones not starting with 3.
As numbers starting with 3 are same in number as the ones starting with other digits 5,7,8 and 9
So the numbers not starting with 3 are 4/5*120=96
Number of 5 digit numbers = 5!=120
Total numbers = 96+120=216
IMO E
Posted from my mobile device
5P4 =120
Numbers greater than 4000 are the ones not starting with 3.
As numbers starting with 3 are same in number as the ones starting with other digits 5,7,8 and 9
So the numbers not starting with 3 are 4/5*120=96
Number of 5 digit numbers = 5!=120
Total numbers = 96+120=216
IMO E
Posted from my mobile device
