Author 
Message 
VP
Joined: 26 Apr 2004
Posts: 1209
Location: Taiwan

How many people are employed at a certain manufacturing [#permalink]
Show Tags
17 May 2004, 19:10
This topic is locked. If you want to discuss this question please repost it in the respective forum.
How many people are employed at a certain manufacturing plant with an annual payroll of $2342000
(1) Threefourths of the employees are clerical, at an average salary of $16020
(2)With 8 percent more employees, the payroll would equal $ 2548000
Is this data sufficient ? thank you



Senior Manager
Joined: 02 Mar 2004
Posts: 327
Location: There

I think, the answer is C. Just a guess!



Manager
Joined: 10 Mar 2004
Posts: 64
Location: Dallas,TX

Re: please give me an hand (Data sufficiency) [#permalink]
Show Tags
18 May 2004, 10:30
chunjuwu wrote: How many people are employed at a certain manufacturing plant with an annual payroll of $2342000
(1) Threefourths of the employees are clerical, at an average salary of $16020
(2)With 8 percent more employees, the payroll would equal $ 2548000
Is this data sufficient ? thank you
I don't think it cannot be solved even by both combined.



Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India

Answer is E
Statement 1... tells about the clerks 'Threefourths of the employees are clerical, at an average salary of $16020 ' Therefore the remaining one forth ... but what is the NUMBER ... hence, insuffnt.
Statement 2 ....'With 8 percent more employees, the payroll would equal $ 2548000' .. from this we can get the payroll of the total employees ....ie. 1.08x=2548000, through which we can calculate the payroll of all .....still we cannot get the whole number of employess.. Not sufficnt.
Combing both also does not give us the number. Hence the answer is E.
_________________
Giving another SHOT



Senior Manager
Joined: 02 Mar 2004
Posts: 327
Location: There

Re: please give me an hand (Data sufficiency) [#permalink]
Show Tags
18 May 2004, 11:29
Let x be the number of employees.
Obviously, x should be a positive integer.
1. x is a multiple of 4. Insufficient.
2. x is a multiple of 25. Insufficient.
Combined 1 and 2: x is a multiple of 100.
(3x/4)16020 + (x/4)y = 2342000
or (3x)(4005)+ (xy/4) = 2342000.
3*200*4005 > 2342000.
There is only one solution, that is, x = 100.
C is the answer.



Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India

Hi Hallelu
To be honest, I cannot understand your explaination .. with the multiple of 4 and multiple of 25...this goes way above my head. Would you be able to provide the source for the multiplication stuff ...its interesting (only if i can know your approach).
Thanks bro
_________________
Giving another SHOT



Senior Manager
Joined: 02 Mar 2004
Posts: 327
Location: There

3/4 of 6 people = 4.25 people.
8% of 10 people = .8 people
I hope, you'll get it.



VP
Joined: 26 Apr 2004
Posts: 1209
Location: Taiwan

I think the answer is E.
set the total people = X and nonclerical employees have the average salary, Y
From A, we can only get:
0.75X * 16020 + 0.25X * Y = 234200
From B we can only get:
1.08X * each employees' salary = 254800
But, we don't know what percentage of the employees are clerical or nonclerical employees; therefore, we can solve the problem.
This answer is E. Does anybody have other thought?



Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India

Hi Hallelujah
You have mentioned the mnumbers "6 people" and "10 people" ....
3/4 of 6 people = 4.25 people.
8% of 10 people = .8 people
I understand the number being a WHOLE number as ... thanks for that...
Now, coming back to your previous post. You have mentioned that "x is a multiple of 100" ... well, it can be 200, 300, 400 ....
But in your last statement, you took it to be 100, why not the other multiples of 100?. I hope I brought the error in your reasoning. Hence the EXACT number cannot be determined with the information given. Making it E as the answer.
Regards
_________________
Giving another SHOT



Senior Manager
Joined: 02 Mar 2004
Posts: 327
Location: There

If the number of employees is more than or equal to 200, the total salary of 3/4 employees is greater than $2342000. Hence, except for 100, all ther positive multiples of 100 are ruled out.



Manager
Joined: 10 Mar 2004
Posts: 64
Location: Dallas,TX

The answer(C) that Hella has given is correct and his solution perfect.
Not sure if such difficult DS can be a part of actual GMAT.
Great work Hella.
cheers



Intern
Joined: 06 May 2004
Posts: 15
Location: Toronto

beautiful solution halle!
_________________
lets do it together....



Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India

Hi Halle
HATS OFF HALLE
I agree and the explaination is clear. Thanks for the insight. Pardon me, if i had been stubborn in proving my point.
Regards
_________________
Giving another SHOT



VP
Joined: 26 Apr 2004
Posts: 1209
Location: Taiwan

Way to go, Halle
you are right,
thank you.



Senior Manager
Joined: 07 Oct 2003
Posts: 350
Location: Manhattan

Re: please give me an hand (Data sufficiency) [#permalink]
Show Tags
31 May 2004, 20:19
hallelujah1234 wrote: Let x be the number of employees.
Obviously, x should be a positive integer.
1. x is a multiple of 4. Insufficient. 2. x is a multiple of 25. Insufficient.
Combined 1 and 2: x is a multiple of 100.
(3x/4)16020 + (x/4)y = 2342000 or (3x)(4005)+ (xy/4) = 2342000.
3*200*4005 > 2342000.
There is only one solution, that is, x = 100.
C is the answer.
Don't mean to beat on a dead horse here, but I missed this one.
Where does the 200 in '3*200*4005>234200 come in?
Also, how do you make the leap to this equation in general? Thanks in advance.



Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India

Ooooooo my gosh .. i am confused in here again. I am abck to straching my head. Can Halle or others be kind enough to explain stepbystep. Please. One request, please explain stepbystep .. I get confused with sudden insertion of 3/4 of 6, or 8% of 10 etc...
Thanks for the patience guys.
Regards
_________________
Giving another SHOT



Senior Manager
Joined: 02 Mar 2004
Posts: 327
Location: There

hallelujah1234 wrote: If the number of employees is more than or equal to 200, the total salary of 3/4 employees is greater than $2342000. Hence, except for 100, all ther positive multiples of 100 are ruled out.
The above explains why not 200, or any positive multiple of 100 except 100.



Manager
Joined: 02 Jun 2004
Posts: 154
Location: san jose,ca

I am new to this forum but not new to math,got some awards in my school days. I see lot of posts here asking to explain in a very detailed way.I have a piece of advice.
Best way to find solutions to a math problem is to analyze it yourself.Even if you dont get the answer, dont give up,try again from all possible angles,start from basics,try again,timing is not the issue when you are in learning mode.Only then, you look for the real answer.Then you will understand what people are talking about.I felt members were asking too spoonfeedy questions (not this thread though).Either they are looking at the forum questions without clearing the basic concepts or they are straightway jumping to the answers.










