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gmatcraze
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How many positive integers can be expressed as a product of 25 Aug 2008, 19:19
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How many positive integers can be expressed as a product of two or more of the primes numbers 5,7,11 and 13 if no one product is to include the same factor more than once?
A) 8 b) 9 c) 10 d) 11 e) 12

I got E as the answer ... don't have the OA to this one ... Please show your approach to solve and help to confirm ...



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ChargePositif
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How many positive integers can be expressed as a product of 25 Aug 2008, 20:13
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gmatcraze
How many positive integers can be expressed as a product of two or more of the primes numbers 5,7,11 and 13 if no one product is to include the same factor more than once?
A) 8 b) 9 c) 10 d) 11 e) 12

I got E as the answer ... don't have the OA to this one ... Please show your approach to solve and help to confirm ...
Show more

I think this is a simple case of permutations. So for this P(4,2) = 4!/(4-2)! = 24/2 = 12.

No?

cP
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x2suresh
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How many positive integers can be expressed as a product of 25 Aug 2008, 20:58
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gmatcraze
How many positive integers can be expressed as a product of two or more of the primes numbers 5,7,11 and 13 if no one product is to include the same factor more than once?
A) 8 b) 9 c) 10 d) 11 e) 12

I got E as the answer ... don't have the OA to this one ... Please show your approach to solve and help to confirm ...
Show more

= 4C2+4C3+4C4
= 6+4+1 =11

Will go for D.

How did you get 12.. Show your steps.
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ChargePositif
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How many positive integers can be expressed as a product of 25 Aug 2008, 21:26
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x2suresh
gmatcraze
How many positive integers can be expressed as a product of two or more of the primes numbers 5,7,11 and 13 if no one product is to include the same factor more than once?
A) 8 b) 9 c) 10 d) 11 e) 12

I got E as the answer ... don't have the OA to this one ... Please show your approach to solve and help to confirm ...

= 4C2+4C3+4C4
= 6+4+1 =11

Will go for D.

How did you get 12.. Show your steps.
Show more

x2suresh is right. This is a combinations problem not a permutations problem. -1 for me. :(

cP
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Nerdboy
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How many positive integers can be expressed as a product of 26 Aug 2008, 01:03
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6 possible number with any two of the prime factors + 4 possible with three of the primes + 1 possible with all four = 11



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!