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GK_Gmat
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vinaym
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After solving the equation, I am getting 2 imaginary roots.
What is the OA?

- Brajesh
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Penny10
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You lost me on your math here:

"Then I squared both sides once again to arrive at:
8x^4+16x^2+9 = 0"

When I squared both sides I got:

4x^4 + 6x^2 + 4 = 4x^2 + 4x =1, which simplifies to:
4x^4 + 2x^2 - 4x + 3 = 0

Descarte's Rule of Signs says that the number of sign changes in a polynomial expression is equal to the max number of roots, or 2 less, or two less than that all the way down to zero. There are 2 sign changes, so its either 2 or 0 (there were no sign changes on the polynomial expression of f(-x).

I could use the rational roots test to come up with all possible roots (it would yeild 6 possibilities) and test them, but I've already spent way more than my alloted 2 minutes, and killersquirrel's logic approach is looking persuasive.

Ahhh... fun with polynomials
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GK_Gmat
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KillerSquirrel
sqrt(x^2 + 1) + sqrt(x^2 + 2) = 2

1. since sqrt(n) can never be less then zero.

2. and x^2 will always give positive value.

x^2 >= 0

sqrt(0^2 + 1) + sqrt(0^2 + 2) = 2

sqrt(1) + sqrt(2) = 2

~ 2.4 > 2 ---> has to be !

I think there are zero solutions for this equation (unless you can use i - irrational numbers)

:)


Fantastic explanation! Thanks a bunch. OA is A.



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